Which command outputs the result of processing a template to a YAML file named mysqlProcessed.yaml?

Which command outputs the result of processing a template to a YAML file named mysqlProcessed.yaml?

• A. oc process -o yaml -f mysql.yaml > mysqlProcessed.yaml
• B. oc process -f mysql.yaml
• C. oc process -o json -f mysql.yaml > mysqlProcessed.yaml
• D. oc create -f mysqlProcessed.yaml

Answer: (A)

Rendering a template and saving its output as a YAML file requires both selecting YAML as the output format and directing the resulting text into a file. The command does exactly that: it processes the template file specified, outputs YAML, and redirects that output into a file named mysqlProcessed.yaml. In OpenShift, oc process reads the template with the -f option, and -o yaml ensures the rendered result is in YAML. Redirecting stdout with > mysqlProcessed.yaml writes that YAML content to the file. Using -o json would produce JSON instead, which wouldn’t match the requested YAML file, and using oc create would try to create resources from the template rather than producing a YAML representation.

Rendering a template and saving its output as a YAML file requires both selecting YAML as the output format and directing the resulting text into a file. The command does exactly that: it processes the template file specified, outputs YAML, and redirects that output into a file named mysqlProcessed.yaml. In OpenShift, oc process reads the template with the -f option, and -o yaml ensures the rendered result is in YAML. Redirecting stdout with > mysqlProcessed.yaml writes that YAML content to the file. Using -o json would produce JSON instead, which wouldn’t match the requested YAML file, and using oc create would try to create resources from the template rather than producing a YAML representation.